x^2+1.26x-0.6=0

Solution for x^2+1.26x-0.6=0 equation:

x^2+1.26x-0.6=0

a = 1; b = 1.26; c = -0.6;
Δ = b2-4ac
Δ = 1.262-4·1·(-0.6)
Δ = 3.9876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.26)-\sqrt{3.9876}}{2*1}=\frac{-1.26-\sqrt{3.9876}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.26)+\sqrt{3.9876}}{2*1}=\frac{-1.26+\sqrt{3.9876}}{2}
$